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When a string is divided into three segments of length l₁, l₂ and l₃ the fundamental frequencies of these three segments are v₁, v₂ and v₃ respectively. The original fundamental frequency (v) of the string is
Options
(a) √v = √v₁ + √v₂ + √v₃
(b) v = v₁ + v₂ + v₃
(c) 1/v = 1/v₁ + 1/v₂ + 1/v₃
(d) 1/ √v = 1/ √v₁ + 1/ √v₂ + 1/ √v₃
Correct Answer:
1/v = 1/v₁ + 1/v₂ + 1/v₃
Explanation:
Fundamental frequency is given by v = 1/ 2l √(T / µ)
⇒ v ∞ 1/ l ⇒ P ∞ 1 / v Since, P divided into l₁, l₂ and l₃ segments.
Here, l = l₁ + l₂ + l₃
So, 1/v = 1/v₁ + 1/v₂ + 1/v₃
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the series resonance the value of impedence is 3 Ω and the resistance is 4Ω,
- Three objects A,B and C are kept in a straight line on a frictionless horizontal surface
- A charged particle of mass m and charge q moves along a circular path of radius
- A body is thrown upward from ground covers equal distances
- The energy released in the fission of 1 kg of ₉₂U²³⁵ is (energy per fission = 200 MeV)
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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