| ⇦ | 
| ⇨ |
When a sound wave of wavelength λ is propagating in a medium, the maximum velocity of the particle is equal to the wave velocity. The amplitude of wave is
Options
(a) λ
(b) λ/2
(c) λ/2π
(d) λ/4π
Correct Answer:
λ/2π
Explanation:
Maximum particle velocity (vₚ)ₘₐₓ = aω
where a is the amplitude of the wave and ω is the angular frequency
Wave velocity, v = λʋ
where λ is the wavelength of a wave and ʋ is a frequency of a wave.
Given : vₚ = v .·. aω = λʋ or a × 2πʋ = λʋ or a = λ/2π
Related Questions: - A photocell employs photoelectric effect to convert
- B is doped in Si or Ge, then we will get
- A boat which has a speed of 5 kmh⁻¹ in still water crosses river of width 1 km long
- Height of geostationary satellite is
- A wire carrying current I has the shape as shown in adjoining figure. Linear parts
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A photocell employs photoelectric effect to convert
- B is doped in Si or Ge, then we will get
- A boat which has a speed of 5 kmh⁻¹ in still water crosses river of width 1 km long
- Height of geostationary satellite is
- A wire carrying current I has the shape as shown in adjoining figure. Linear parts
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply