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When a mass M is attached to the spring of force constant k, then the spring stretches by l. If the mass oscillates with amplitude l, what will be the maximum potential energy stored in the spring?
Options
(a) kl/2
(b) 2kl
(c) 1/2 Mgl
(d) Mgl
Correct Answer:
Mgl
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A wire of resistance 4 ohm is stretched to twice its original length.
- A particle is moving in a circle with uniform speed v. In moving from a point to another
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- An avarage induced e.m.f. of 1 V appears in a coil when the current in it is changed
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Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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initially spring is at rest . when we attach mass of m to it then in order to have maximum amplitude l the spring must have to stretch by a length 2l so maximum potential energy in the spring should be 1/2 k x^2 put x=2l and mg=2lk
FINAL ANSWER IS Mgl
good