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The escape velocity of a body from earth’s surface is Ve. The escape velocity of the same body from a height equal to 7R from earth’s surface will be
Options
(a) Ve/√2
(b) Ve/2
(c) Ve/2√2
(d) Ve/4
Correct Answer:
Ve/2√2
Explanation:
Escape velocity of body from the earth’s surface is Ve=√2gR
Escape velocity of a same body at a height h from the earth’s surface is,Ve’=√2gR²/R+h
Given h=7R
Ve’=√2gR²/R+7R ⇒ √2gR²/R[1+7]
=√2gR/8 ⇒ 1/2√2 √2gR
=1/2√2 Ve.
Related Questions: - Out of the following which pair of quantities does not have same dimensions?
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Out of the following which pair of quantities does not have same dimensions?
- A Zenor diode has a contact potential of 1 V in the absence of biasing. It undergoes
- When an electron beam passes through an electric field they gain kinetic energy.
- When photons of energy hν are incident on the surface of photosensitive
- A body rolls down a stair case of 5 steps. Each step has height 0.1 m and width 0.1m
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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