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When a mass M is attached to the spring of force constant k, then the spring stretches by l. If the mass oscillates with amplitude l, what will be the maximum potential energy stored in the spring?
Options
(a) kl/2
(b) 2kl
(c) 1/2 Mgl
(d) Mgl
Correct Answer:
Mgl
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Subject: Physics
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- The kirchoff’s first law (∑i=0) and second law (∑iR=∑E), where the symbols
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- A coil of 40 henry inductance is connected in series with a resistance of 8 ohm
- The mean free path of molecules of a gas,(radius ‘r’) is inversely proportional to
- A bullet of mass m moving with velocity v strikes a block of mass M at rests
Topics: Work Energy and Power (94)
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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initially spring is at rest . when we attach mass of m to it then in order to have maximum amplitude l the spring must have to stretch by a length 2l so maximum potential energy in the spring should be 1/2 k x^2 put x=2l and mg=2lk
FINAL ANSWER IS Mgl
good