| ⇦ | 
| ⇨ |
When 22.4 litres of H₂(g) is mixed with 11.2 litres of Cl₂(g) each at S.T.P, the moles of HCl(g) formed is equal to
Options
(a) 1 mol of HCl(g)
(b) 2 mol of HCl(g)
(c) 0.5 mol of HCl(g)
(d) 1.5 mol of HCl(g)
Correct Answer:
1 mol of HCl(g)
Explanation:
H₂ +Cl₂ → 2HCl
t=0 ,22.4,11.2 lit , 0
t=0,or 1 mole, 0.5 mole, 0
at time t (1-0.5) =0.5
0.5×2 = 1 mole
Related Questions: - Oxidation number of chromium in Na₂Cr₂O₇ is
- 100 mL of HCl + 35 mL of NaOH, colour of methyl orange in the solution will be
- The increasing order of atomic radius for the elements Na, Rb, K and Mg is
- Which of the following gives propyne on hydrolysis
- Oxidation number of iron in [Fe(CN)₆]⁴⁻ is
Topics: Some Basic concepts of Chemistry
(5)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Oxidation number of chromium in Na₂Cr₂O₇ is
- 100 mL of HCl + 35 mL of NaOH, colour of methyl orange in the solution will be
- The increasing order of atomic radius for the elements Na, Rb, K and Mg is
- Which of the following gives propyne on hydrolysis
- Oxidation number of iron in [Fe(CN)₆]⁴⁻ is
Topics: Some Basic concepts of Chemistry (5)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply