| ⇦ | 
| ⇨ |
When 1 mol of gas is heated at constant volume, temperature is raised from 298 to 308 K. Heat supplied to the gas is 500J. Then which statement is correct
Options
(a) q = w = 500 J,ΔU = 0
(b) q = ΔU = 500 J,W = 0
(c) q = w = 500 J ,ΔU = 0
(d) ΔU = 0, q = w = -500J
Correct Answer:
q = ΔU = 500 J,W = 0
Explanation:
We known that ΔH = ΔE + PV
ΔH = ΔE + P Δ V + V Δ P =0
When ΔV = 0; w = 0. Therefore ΔH = ΔE + PΔV
ΔH = ΔE + 0 or ΔH = ΔE.
As ΔE = q + w , ΔE = q.
In the present problem, ΔH = 500J,
ΔV = ΔE = 500 J,q = 500 J, w = 0.
Related Questions: - The number of significant figures for the three numbers 161 cm, 0.161 cm
- Copper pyrite, the chief ore of copper, is
- A unit cell of sodium chloride has four formula units.The edge length of the unit cell
- In the conversion of Br₂ to BrO₃⁻, the oxidation number of Br changes from
- Chemical A is used for water softening to remove temporary hardness.
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The number of significant figures for the three numbers 161 cm, 0.161 cm
- Copper pyrite, the chief ore of copper, is
- A unit cell of sodium chloride has four formula units.The edge length of the unit cell
- In the conversion of Br₂ to BrO₃⁻, the oxidation number of Br changes from
- Chemical A is used for water softening to remove temporary hardness.
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply