| ⇦ |
| ⇨ |
What is the magnetic moment for Mn²⁺ ion in low spin state
Options
(a) 5.90 BM
(b) 8.90 BM
(c) 2.8 BM
(d) 1.73 BM
Correct Answer:
1.73 BM
Explanation:
For Mn²⁺ ion in low spin state, number of unpaired electrons = 1. Magnetic moment = √n(n+2) =√1*3=1.73 BM.
Related Questions: - Chlorobenzene can be prepared by reacting aniline with
- The reaction in which hydrogen peroxide acts as a reducing agent is
- Action of nitrous acid on ethyl amine gives
- The most common lanthanide is
- Ziegler Natta catalyst is an organometallic compound containing
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Chlorobenzene can be prepared by reacting aniline with
- The reaction in which hydrogen peroxide acts as a reducing agent is
- Action of nitrous acid on ethyl amine gives
- The most common lanthanide is
- Ziegler Natta catalyst is an organometallic compound containing
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply