| ⇦ | 
| ⇨ |
What is the magnetic moment for Mn²⁺ ion in low spin state
Options
(a) 5.90 BM
(b) 8.90 BM
(c) 2.8 BM
(d) 1.73 BM
Correct Answer:
1.73 BM
Explanation:
For Mn²⁺ ion in low spin state, number of unpaired electrons = 1. Magnetic moment = √n(n+2) =√1*3=1.73 BM.
Related Questions: - Reaction of a carbonyl compound with one of the following reagents involves
- The orthophosphoric acid is a
- Which of the following coordination compounds would exhibit optical isomerism
- A ideal gas will have maximum density when
- DDT is prepared by reacting chlorobenzen with
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Reaction of a carbonyl compound with one of the following reagents involves
- The orthophosphoric acid is a
- Which of the following coordination compounds would exhibit optical isomerism
- A ideal gas will have maximum density when
- DDT is prepared by reacting chlorobenzen with
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply