| ⇦ |
| ⇨ |
What is the magnetic moment for Mn²⁺ ion in low spin state
Options
(a) 5.90 BM
(b) 8.90 BM
(c) 2.8 BM
(d) 1.73 BM
Correct Answer:
1.73 BM
Explanation:
For Mn²⁺ ion in low spin state, number of unpaired electrons = 1. Magnetic moment = √n(n+2) =√1*3=1.73 BM.
Related Questions: - Formalin is a
- Equal volumes of 0.1 M AgNO₃ and 0.2 M NaCl are mixed
- In an exothermic reaction
- The equilibrium constant of a reaction is 300. If the volume of a reaction flask
- An organic compound gives Molisch’s test as well as Benedict’s test.
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Formalin is a
- Equal volumes of 0.1 M AgNO₃ and 0.2 M NaCl are mixed
- In an exothermic reaction
- The equilibrium constant of a reaction is 300. If the volume of a reaction flask
- An organic compound gives Molisch’s test as well as Benedict’s test.
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply