| ⇦ | 
| ⇨ |
Sea weeds are an important source of
Options
(a) fluorine
(b) bromine
(c) sulphur
(d) iodine
Correct Answer:
iodine
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Which of the following is dihydric alcohol
- Two possible stereo-structures of CH₃CHOHCOOH, Which are optically active are called
- During the decomposition of H₂O₂ to give oxygen, 48 g O₂ is formed per minute
- MnO₄²⁻ (1 mole) in neutral aqueous medium is disproportionated to
- Reduction by LiAlH₄ of hydrolysed product of an ester gives
Topics: Surface Chemistry and Isolation of Elements
(88)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is dihydric alcohol
- Two possible stereo-structures of CH₃CHOHCOOH, Which are optically active are called
- During the decomposition of H₂O₂ to give oxygen, 48 g O₂ is formed per minute
- MnO₄²⁻ (1 mole) in neutral aqueous medium is disproportionated to
- Reduction by LiAlH₄ of hydrolysed product of an ester gives
Topics: Surface Chemistry and Isolation of Elements (88)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply