| ⇦ |
| ⇨ |
What is the energy released by fission of 1 g of U²³⁵? (Assume 200 MeV energy is liberated on fission of 1 nucleus)
Options
(a) 2.26×10⁴ kWh
(b) 1.2×10⁴ kWh
(c) 4.5×10⁴ kWh
(d) 2.5×10⁴ kWh
Correct Answer:
2.26×10⁴ kWh
Explanation:
Energy released in one fission of ₉₂U²³⁵ nucleus = 200 MeV
Mass of uranium = 1g
We know that, 235 g of U²³⁵ has 6.023 × 10²³ atoms of nuclei.
Energy released in fission of 1g of U²³⁵,
E = (6.023 × 10²³ × 1 × 200) / 235 = 5.1 × 10²³ MeV
= 5.1 × 10²³ × 1.6 × 10⁻³ J
= [(5.1 × 10²³ × 1.6 × 10⁻³) / 3.6 × 10⁶] kWh
= 2.26 × 10⁴ kWh
Related Questions: - The potential energy of a long spring when stretched by 2 cm is U.
- A thin film of soap solution (n=1.4) lies on the top of a glass plate (n=1.5).
- An ideal spring with spring constant K is hung from the ceiling and a block of mass
- An adiabatic process occurs at constant
- A circular road of radius 1000m has banking angle 45°.The maximum safe speed of a car
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The potential energy of a long spring when stretched by 2 cm is U.
- A thin film of soap solution (n=1.4) lies on the top of a glass plate (n=1.5).
- An ideal spring with spring constant K is hung from the ceiling and a block of mass
- An adiabatic process occurs at constant
- A circular road of radius 1000m has banking angle 45°.The maximum safe speed of a car
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply