| ⇦ | 
| ⇨ |
What is the energy released by fission of 1 g of U²³⁵? (Assume 200 MeV energy is liberated on fission of 1 nucleus)
Options
(a) 2.26×10⁴ kWh
(b) 1.2×10⁴ kWh
(c) 4.5×10⁴ kWh
(d) 2.5×10⁴ kWh
Correct Answer:
2.26×10⁴ kWh
Explanation:
Energy released in one fission of ₉₂U²³⁵ nucleus = 200 MeV
Mass of uranium = 1g
We know that, 235 g of U²³⁵ has 6.023 × 10²³ atoms of nuclei.
Energy released in fission of 1g of U²³⁵,
E = (6.023 × 10²³ × 1 × 200) / 235 = 5.1 × 10²³ MeV
= 5.1 × 10²³ × 1.6 × 10⁻³ J
= [(5.1 × 10²³ × 1.6 × 10⁻³) / 3.6 × 10⁶] kWh
= 2.26 × 10⁴ kWh
Related Questions: - The additional energy that should be given to an electron to reduce its de-Broglie
- Certain quantity of water cools from 70⁰ C to 60⁰C in the first 5 minutes and to 54⁰C
- A body of mass m slides down an incline and reaches the bottom
- At what angle should the two forces 2P and √2 P act,so that the resultant force is P√10?
- In a primary coil 5 A current is flowing on 220 V. In the secondary coil 2200 V
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The additional energy that should be given to an electron to reduce its de-Broglie
- Certain quantity of water cools from 70⁰ C to 60⁰C in the first 5 minutes and to 54⁰C
- A body of mass m slides down an incline and reaches the bottom
- At what angle should the two forces 2P and √2 P act,so that the resultant force is P√10?
- In a primary coil 5 A current is flowing on 220 V. In the secondary coil 2200 V
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply