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What is the energy released by fission of 1 g of U²³⁵? (Assume 200 MeV energy is liberated on fission of 1 nucleus)
Options
(a) 2.26×10⁴ kWh
(b) 1.2×10⁴ kWh
(c) 4.5×10⁴ kWh
(d) 2.5×10⁴ kWh
Correct Answer:
2.26×10⁴ kWh
Explanation:
Energy released in one fission of ₉₂U²³⁵ nucleus = 200 MeV
Mass of uranium = 1g
We know that, 235 g of U²³⁵ has 6.023 × 10²³ atoms of nuclei.
Energy released in fission of 1g of U²³⁵,
E = (6.023 × 10²³ × 1 × 200) / 235 = 5.1 × 10²³ MeV
= 5.1 × 10²³ × 1.6 × 10⁻³ J
= [(5.1 × 10²³ × 1.6 × 10⁻³) / 3.6 × 10⁶] kWh
= 2.26 × 10⁴ kWh
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A 36 Ω galvanometer is shunted by resistance of 4 Ω. The percentage of the total current
- An air core solenoid has 1000 turns and is one meter long. Its cross sectional area
- A simple pendulum has a time period T₁ when on the earth’s surface and T₂ When taken
- A circular disc of radius R is removed from a bigger circular disc of radius 2R
- The half-life period of a radio-active element X is same as the mean life time
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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