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What is the energy released by fission of 1 g of U²³⁵? (Assume 200 MeV energy is liberated on fission of 1 nucleus)
Options
(a) 2.26×10⁴ kWh
(b) 1.2×10⁴ kWh
(c) 4.5×10⁴ kWh
(d) 2.5×10⁴ kWh
Correct Answer:
2.26×10⁴ kWh
Explanation:
Energy released in one fission of ₉₂U²³⁵ nucleus = 200 MeV
Mass of uranium = 1g
We know that, 235 g of U²³⁵ has 6.023 × 10²³ atoms of nuclei.
Energy released in fission of 1g of U²³⁵,
E = (6.023 × 10²³ × 1 × 200) / 235 = 5.1 × 10²³ MeV
= 5.1 × 10²³ × 1.6 × 10⁻³ J
= [(5.1 × 10²³ × 1.6 × 10⁻³) / 3.6 × 10⁶] kWh
= 2.26 × 10⁴ kWh
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A cricketer catches a ball of mass 150 g in 0.1 sec moving with speed 20 m/s
- A particle executes simple harmonic oscillations with an amplitude
- A rocket with a lift-off mass 3.5 x 10⁴ kg is blasted upwards with an initial acceleration
- An ideal spring with spring constant K is hung from the ceiling and a block of mass
- The energy released in the fission of 1 kg of ₉₂U²³⁵ is (energy per fission = 200 MeV)
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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