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What is the energy released by fission of 1 g of U²³⁵? (Assume 200 MeV energy is liberated on fission of 1 nucleus)
Options
(a) 2.26×10⁴ kWh
(b) 1.2×10⁴ kWh
(c) 4.5×10⁴ kWh
(d) 2.5×10⁴ kWh
Correct Answer:
2.26×10⁴ kWh
Explanation:
Energy released in one fission of ₉₂U²³⁵ nucleus = 200 MeV
Mass of uranium = 1g
We know that, 235 g of U²³⁵ has 6.023 × 10²³ atoms of nuclei.
Energy released in fission of 1g of U²³⁵,
E = (6.023 × 10²³ × 1 × 200) / 235 = 5.1 × 10²³ MeV
= 5.1 × 10²³ × 1.6 × 10⁻³ J
= [(5.1 × 10²³ × 1.6 × 10⁻³) / 3.6 × 10⁶] kWh
= 2.26 × 10⁴ kWh
Related Questions: - Three capacitors of capacitances 3 μF, 10 μF and 15 μF are connected in series
- A uranium nucleus ₉₂ U ²³⁸ emits an α-particle and a β-particle in succession.
- The acceleration due to gravity becomes (g/2) where g=acceleration due to gravity
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Three capacitors of capacitances 3 μF, 10 μF and 15 μF are connected in series
- A uranium nucleus ₉₂ U ²³⁸ emits an α-particle and a β-particle in succession.
- The acceleration due to gravity becomes (g/2) where g=acceleration due to gravity
- The work done in which of the following processes is zero?
- 4 point charges each +q is placed on the circumference of a circle
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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