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For the normal eye, the cornea of eye provides a converging power of 40D and the least converging power of the eye lens behind the cornea is 20D. Using this information, the distance between the retina and the eye lens of the eye can be estimated to be:
Options
(a) 2.5 cm
(b) 1.67 cm
(c) 1.5 cm
(d) 5 cm
Correct Answer:
2.5 cm
Explanation:
1/f = 1/v – 1/u
= 1/ 1 / 40 = 1/u
u = 1/40 m = 2.5 m
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Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An experiment takes 10 minutes to raise temperature of water from 0⁰C to 100⁰C
- The displacement of particle is given by x=aₒ+(a₁t/2)-(a₂t²/3) what is acceleration?
- The decreasing order of wavelength of infrared, microwave, ultraviolet and gamma
- Two charges each equal to 2µ C are 0.5m apart. If both of them exist inside vacuum
- Calculate the charge on equivalent capacitance of the conbination shown in figure
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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