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For the normal eye, the cornea of eye provides a converging power of 40D and the least converging power of the eye lens behind the cornea is 20D. Using this information, the distance between the retina and the eye lens of the eye can be estimated to be:
Options
(a) 2.5 cm
(b) 1.67 cm
(c) 1.5 cm
(d) 5 cm
Correct Answer:
2.5 cm
Explanation:
1/f = 1/v – 1/u
= 1/ 1 / 40 = 1/u
u = 1/40 m = 2.5 m
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Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In an unbiased p-n junction, holes diffuse from the p-region to n-region because of
- A ray enters a glass sphere of refractive index μ=√3 at an angle of incidence of 60⁰
- What will be the ratio of the distance moved by a freely falling body from rest in 4th
- A charged particle (charge q) is moving in a circle of radius R with uniform speed v
- In a common emitter transistor amplifier, the voltage gain is
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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