| ⇦ | 
| ⇨ |
Two wires of equal length and equal diameter and having resistivities ρ₁ and ρ₂ are connected in series. The equivalent resistivity of the combination is
Options
(a) ρ₁+ρ₂/2
(b) ρ₁+ρ₂
(c) ρ₁ρ₂/ρ₁+ρ₂
(d) √ρ₁ρ₂
Correct Answer:
ρ₁+ρ₂/2
Explanation:
The resistance of two wires are
R₁ = ρ₁ (l / A) and R₂ = ρ₂ (l / A)
Now, equivalent resistance of series connection of wire
Req = R₁ + R₂ = ρ₁ (l / A) + ρ₂ (l / A) = (l / A) (ρ₁ + ρ₂)
The equivalent resistance Req can be given by Req = ρ(eq) (l / A)
⇒ ρ(eq) (l / A) = (l / A) (ρ₁ + ρ₂)
Hence, ρ(eq) = (ρ₁ + ρ₂) / 2
Related Questions: - A jar is filled with two non-mixing liquids 1 and 2 having densities
- α-particles, deuterons and protons of same energy are moving in a perpendicular
- In communication with help of antenna if height is doubled then the range
- Pure Si at 300 k has equal electrons (nₑ) and hole (nh) concentrations
- The ionization energy of Li⁺⁺ is equal to
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A jar is filled with two non-mixing liquids 1 and 2 having densities
- α-particles, deuterons and protons of same energy are moving in a perpendicular
- In communication with help of antenna if height is doubled then the range
- Pure Si at 300 k has equal electrons (nₑ) and hole (nh) concentrations
- The ionization energy of Li⁺⁺ is equal to
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply