| ⇦ |
| ⇨ |
Two spherical bodies of mass M and 5 M and radii R and 2 R released in free space with initial separation between their centres equal to 12 R. If they attract each other due to gravitational force only, then the distance covered by the smaller body before collision is
Options
(a) 4.5 R
(b) 7.5 R
(c) 1.5 R
(d) 2.5 R
Correct Answer:
7.5 R
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In the relation n=PV/RT, n stands for
- Four identical rods are joined to from a square. If the temperature difference
- Two spheres A and B of masses m and m respectively collide. A is at rest initially
- In a vessel, the gas is at a pressure P. If the mass of all the molecules
- The acceleration due to gravity near the surface of a planet of radius R and density d
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the relation n=PV/RT, n stands for
- Four identical rods are joined to from a square. If the temperature difference
- Two spheres A and B of masses m and m respectively collide. A is at rest initially
- In a vessel, the gas is at a pressure P. If the mass of all the molecules
- The acceleration due to gravity near the surface of a planet of radius R and density d
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply