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On bombarding U²³⁵ by slow neutron, 200 MeV energy is released. If the power output of atomic reactor is 1.6 MW, then the rate of fission will be
Options
(a) 8×10¹⁶/s
(b) 20×10¹⁶/s
(c) 5×10²²/s
(d) 5×10¹⁶/s
Correct Answer:
5×10¹⁶/s
Explanation:
Energy released per fission of uranium = 200 × 10⁶ × 1 × 10⁻¹⁹ J
Power output = 1.6 × 10⁶ W
Number of fission /s = 1.6 × 10⁶ / 200 × 10⁶ × 1 × 10⁻¹⁹ = 5 × 10¹⁶ /s
This is the rate of fission.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If h is planck’s constant and λ is wavelength, h/λ has dimensions of
- Two blocks of masses m₁=4 kg and m₂= 2kg are connected to the ends of a string
- Two stones of masses m and 2m are whirled in horizontal circles, the heavier one
- Radii of curvature of a converging lens are in the rato 1:2. Its focal length
- A body of mass 4 kg is accelerated upon by a constant force travels
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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