| ⇦ | 
| ⇨ |
On bombarding U²³⁵ by slow neutron, 200 MeV energy is released. If the power output of atomic reactor is 1.6 MW, then the rate of fission will be
Options
(a) 8×10¹⁶/s
(b) 20×10¹⁶/s
(c) 5×10²²/s
(d) 5×10¹⁶/s
Correct Answer:
5×10¹⁶/s
Explanation:
Energy released per fission of uranium = 200 × 10⁶ × 1 × 10⁻¹⁹ J
Power output = 1.6 × 10⁶ W
Number of fission /s = 1.6 × 10⁶ / 200 × 10⁶ × 1 × 10⁻¹⁹ = 5 × 10¹⁶ /s
This is the rate of fission.
Related Questions: - In a given process on an ideal gas, dW=0 and dQ<0. Then for the gas
- A Carnot engine takes heat from a reservoir at 627⁰C and rejects heat
- An electric dipole of dipole moment p is placed in a uniform external electric field
- If an electron in a hydrogen atom jumps from the 3rd orbit to the 2nd orbit, it emits
- The ‘rad’ is the correct unit used to report the measurement of
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a given process on an ideal gas, dW=0 and dQ<0. Then for the gas
- A Carnot engine takes heat from a reservoir at 627⁰C and rejects heat
- An electric dipole of dipole moment p is placed in a uniform external electric field
- If an electron in a hydrogen atom jumps from the 3rd orbit to the 2nd orbit, it emits
- The ‘rad’ is the correct unit used to report the measurement of
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply