| ⇦ | 
| ⇨ |
On bombarding U²³⁵ by slow neutron, 200 MeV energy is released. If the power output of atomic reactor is 1.6 MW, then the rate of fission will be
Options
(a) 8×10¹⁶/s
(b) 20×10¹⁶/s
(c) 5×10²²/s
(d) 5×10¹⁶/s
Correct Answer:
5×10¹⁶/s
Explanation:
Energy released per fission of uranium = 200 × 10⁶ × 1 × 10⁻¹⁹ J
Power output = 1.6 × 10⁶ W
Number of fission /s = 1.6 × 10⁶ / 200 × 10⁶ × 1 × 10⁻¹⁹ = 5 × 10¹⁶ /s
This is the rate of fission.
Related Questions: - Electrons in the atom are held to the nucleus by
- The magnifying power of a convex lens of focal length 10 cm, when the image
- A magnet of length 10 cm and magnetic moment 1 A-m² is placed
- A thin rod of length L and mass M is bent at its midpoint into two halves
- Out of the following which pair of quantities does not have same dimensions?
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Electrons in the atom are held to the nucleus by
- The magnifying power of a convex lens of focal length 10 cm, when the image
- A magnet of length 10 cm and magnetic moment 1 A-m² is placed
- A thin rod of length L and mass M is bent at its midpoint into two halves
- Out of the following which pair of quantities does not have same dimensions?
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply