| ⇦ |
| ⇨ |
A block of mass 10 kg is moving in X-direction with a constant speed of 10 ms⁻¹.It is subjected to a retarding force F=-0.1 x m⁻¹, during its travel from x=20m to x=30m.Its final kinetic energy will be
Options
(a) 475 j
(b) 450 j
(c) 275 j
(d) 250 j
Correct Answer:
475 j
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The internal energy change in a system that has absorbed 2 kcals of heat
- A man throws balls with the same speed vertically upwards one after the other
- A metal conductor of length 1m rotates vertically about one of its ends at angular
- In electromagnetic spectrum, the frequencies of γ-rays and x-rays and ultraviolet rays
- A particle moving in a straight line covers half the distance with speed of 3 m/s
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The internal energy change in a system that has absorbed 2 kcals of heat
- A man throws balls with the same speed vertically upwards one after the other
- A metal conductor of length 1m rotates vertically about one of its ends at angular
- In electromagnetic spectrum, the frequencies of γ-rays and x-rays and ultraviolet rays
- A particle moving in a straight line covers half the distance with speed of 3 m/s
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

a=0.1x/m
=0.1/10=0.01 m/s2
v2=100-0.01[30×30-20×20]
=100-0.01×500
=100-5=95
final kinetic energy =1/2x10x95
=475J