| ⇦ | 
| ⇨ |
Two simple harmonic motions of angular frequency 100 and 1000 rad s⁻¹ have the same displacement amplitude. The ratio of other maximum accelerations is:
Options
(a) 1 : 10
(b) 1 : 10²
(c) 1 : 10³
(d) 1 : 10⁴
Correct Answer:
1 : 10²
Explanation:
Maximum acceleration of a particle in the simple harmonic motion is directly proportional to the square of angular frequency i.e., a(max)= – w ² A
As A remains same, we can say
a₁ / a₂ = w₁² / w₂² = (100)² / (1000)² = 1 / 100
⇒ a₁ : a₂ = 1 : 10²
Related Questions: - A particle is released from rest from a tower of height h, i.e,t₁ : t₂ : t₃ is
- Dependence of intensity of gravitational field (E) of earth with distance(r)
- In the diffraction pattern of a single slit
- If the sodium light in Young’s double slit experiment is replaced by red light
- A satellite in a circular orbit of radius R has a period of 4 hours. Another satellite
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle is released from rest from a tower of height h, i.e,t₁ : t₂ : t₃ is
- Dependence of intensity of gravitational field (E) of earth with distance(r)
- In the diffraction pattern of a single slit
- If the sodium light in Young’s double slit experiment is replaced by red light
- A satellite in a circular orbit of radius R has a period of 4 hours. Another satellite
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply