⇦ | ⇨ |
Two simple harmonic motions of angular frequency 100 and 1000 rad s⁻¹ have the same displacement amplitude. The ratio of other maximum accelerations is:
Options
(a) 1 : 10
(b) 1 : 10²
(c) 1 : 10³
(d) 1 : 10⁴
Correct Answer:
1 : 10²
Explanation:
Maximum acceleration of a particle in the simple harmonic motion is directly proportional to the square of angular frequency i.e., a(max)= – w ² A
As A remains same, we can say
a₁ / a₂ = w₁² / w₂² = (100)² / (1000)² = 1 / 100
⇒ a₁ : a₂ = 1 : 10²
Related Questions: - Charge density for intrinsic semiconductor will be
- The resistance of an ammeter is 13Ω and its scale is graduated for a current
- If emf induced in a coil is 2 V by changing the current in it from 8 A to 6 A
- A liquid boils when its vapour pressure equals
- Masses of 3 wires of same metal are in the ratio 1:2:3 and their lengths
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Charge density for intrinsic semiconductor will be
- The resistance of an ammeter is 13Ω and its scale is graduated for a current
- If emf induced in a coil is 2 V by changing the current in it from 8 A to 6 A
- A liquid boils when its vapour pressure equals
- Masses of 3 wires of same metal are in the ratio 1:2:3 and their lengths
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply