| ⇦ | 
| ⇨ |
Two resistors of 6Ω and 9Ω are connected in series to a 120 V source. The power consumed by 6Ω resistor is
Options
(a) 384Ω
(b) 616Ω
(c) 1500Ω
(d) 1800Ω
Correct Answer:
384Ω
Explanation:
Equivalent resistance in series = 6 + 9 = 15 Ω
Current flow in circuit, i = V / R = 120 / 15 = 8 A
Voltage in 6Ω resistor, V = iR = 8 × 6 = 48 V
Power consumed by 6Ω resistor,
P = V² / R = (48 × 48) / 6 = 8 × 48 = 384 W
Related Questions: - A particle of mass m is projected with a velocity v making an angle of 45°
- The number of beta particles emitted by a radioactive substance is twice the number
- What determines the nature of the path followed by the particle?
- A body initially at rest is moving with uniform acceleration a m/s²
- An object placed at 20 cm in front of a concave mirror produces three times
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle of mass m is projected with a velocity v making an angle of 45°
- The number of beta particles emitted by a radioactive substance is twice the number
- What determines the nature of the path followed by the particle?
- A body initially at rest is moving with uniform acceleration a m/s²
- An object placed at 20 cm in front of a concave mirror produces three times
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply