Two resistors of 6Ω and 9Ω are connected in series to a 120 V source.

Two Resistors Of 6 And 9 Are Connected In Series Physics Question

Two resistors of 6Ω and 9Ω are connected in series to a 120 V source. The power consumed by 6Ω resistor is

Options

(a) 384Ω
(b) 616Ω
(c) 1500Ω
(d) 1800Ω

Correct Answer:

384Ω

Explanation:

Equivalent resistance in series = 6 + 9 = 15 Ω

Current flow in circuit, i = V / R = 120 / 15 = 8 A

Voltage in 6Ω resistor, V = iR = 8 × 6 = 48 V

Power consumed by 6Ω resistor,

P = V² / R = (48 × 48) / 6 = 8 × 48 = 384 W

Related Questions:

  1. The coefficient of performance of a Carnot refrigerator working between 30⁰C and 0⁰C is
  2. If the angular momentum of any rotating body increase by 200 % , then the increase
  3. For a transformer, the turns ratio is 3 and its efficiency is 0.75. The current flowing
  4. A boat taken 2h to travel 8km and back in still water.If the velocity of water 4 km/h
  5. If potential(in volts) in a region is expressed as V(x,y,z) = 6xy – y + 2yz,

Topics: Current Electricity (136)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*