| ⇦ |
| ⇨ |
Two resistors of 6Ω and 9Ω are connected in series to a 120 V source. The power consumed by 6Ω resistor is
Options
(a) 384Ω
(b) 616Ω
(c) 1500Ω
(d) 1800Ω
Correct Answer:
384Ω
Explanation:
Equivalent resistance in series = 6 + 9 = 15 Ω
Current flow in circuit, i = V / R = 120 / 15 = 8 A
Voltage in 6Ω resistor, V = iR = 8 × 6 = 48 V
Power consumed by 6Ω resistor,
P = V² / R = (48 × 48) / 6 = 8 × 48 = 384 W
Related Questions: - The ratio of the nuclear radii of elements with mass numbers 216 and 125 is
- Which one of the following bonds produces a solid that reflects light in the visible region
- The time period of a thin bar magnet in Earth’s magnetic field is T
- Electromagnetic induction is not used in
- The slope of the graph showing the variation of potential difference V on X-axis
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of the nuclear radii of elements with mass numbers 216 and 125 is
- Which one of the following bonds produces a solid that reflects light in the visible region
- The time period of a thin bar magnet in Earth’s magnetic field is T
- Electromagnetic induction is not used in
- The slope of the graph showing the variation of potential difference V on X-axis
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply