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Two resistors of 6Ω and 9Ω are connected in series to a 120 V source. The power consumed by 6Ω resistor is
Options
(a) 384Ω
(b) 616Ω
(c) 1500Ω
(d) 1800Ω
Correct Answer:
384Ω
Explanation:
Equivalent resistance in series = 6 + 9 = 15 Ω
Current flow in circuit, i = V / R = 120 / 15 = 8 A
Voltage in 6Ω resistor, V = iR = 8 × 6 = 48 V
Power consumed by 6Ω resistor,
P = V² / R = (48 × 48) / 6 = 8 × 48 = 384 W
Related Questions: - Three solids of masses m₁,m₂ and m₃ are connected with weightless string
- A coil of 40 henry inductance is connected in series with a resistance of 8 ohm
- When sound is produced in an aeroplane with a velocity of 200 m/s horizontally,
- Ohm’s law valid
- A flywheel rotating about a fixed axis has a kinetic energy of 360 J when
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Three solids of masses m₁,m₂ and m₃ are connected with weightless string
- A coil of 40 henry inductance is connected in series with a resistance of 8 ohm
- When sound is produced in an aeroplane with a velocity of 200 m/s horizontally,
- Ohm’s law valid
- A flywheel rotating about a fixed axis has a kinetic energy of 360 J when
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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