| ⇦ | 
| ⇨ |
In the series resonance the value of impedence is 3 Ω and the resistance is 4Ω, then the value of power factor of the circuit is
Options
(a) (4/3)
(b) (3/4)
(c) zero
(d) infinity
Correct Answer:
(4/3)
Explanation:
Power factor cos ɸ = Resistance / Impedance = 4 / 3.
Related Questions: - If R is the radius of earth, the height at which the weight of a body 1/4 of its weight
- Two tangent galvanometers A and B have coils of radii 8 cm and 16 cm respectively
- The polarising angle of glass is 57⁰. A ray of light which is incident at this angle
- Two bubbles A and B (A>B) are joined through a narrow tube. Then
- The wave described by y = 0.25 sin (10 2πx – 2πt), where x and y are in meters
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If R is the radius of earth, the height at which the weight of a body 1/4 of its weight
- Two tangent galvanometers A and B have coils of radii 8 cm and 16 cm respectively
- The polarising angle of glass is 57⁰. A ray of light which is incident at this angle
- Two bubbles A and B (A>B) are joined through a narrow tube. Then
- The wave described by y = 0.25 sin (10 2πx – 2πt), where x and y are in meters
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply