| ⇦ |
| ⇨ |
Two nuclei have their mass numbers into the ratio of 1:3. The ratio of their nucleus densities would be
Options
(a) 1 : 3
(b) 3 : 1
(c) (3)¹/³ : 1
(d) 1 : 1
Correct Answer:
1 : 1
Explanation:
Required ratio of nuclear densities = ρ₁ / ρ₂
(M₁ / V₁) / (M₂ / V₂) = M₁ / M₂ x V₂ / V₁ = 1/3 x 4/3 πR₂³ / 4/3 πR₁³
1/3 x (R₂ / R₁)³ = 1/3 x (R₀M₂¹/³ / R₀M₁¹/³)³ [ R = R₀M¹/³ ]
= 1/3 x (M₂ / M₁) = 1/3 x (3/1) = 1 : 1
Related Questions: - Find the fundamental frequency of a closed pipe if the length of air column is 42m.
- In potentiometer experiment, a cell of emf 1.25V gives balancing length of 30 cm
- In Young’s double slit experiment the distance between the slits and the screen
- 1 curie is equal to
- In a diffraction pattern due to a singleslit of width a, the first minimum is observed
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Find the fundamental frequency of a closed pipe if the length of air column is 42m.
- In potentiometer experiment, a cell of emf 1.25V gives balancing length of 30 cm
- In Young’s double slit experiment the distance between the slits and the screen
- 1 curie is equal to
- In a diffraction pattern due to a singleslit of width a, the first minimum is observed
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply