| ⇦ | 
| ⇨ |
In potentiometer experiment, a cell of emf 1.25V gives balancing length of 30 cm. If the cell is replaced by another cell, then balancing length is found to be 40cm. What is the emf of second cell?
Options
(a) ≈1.5V
(b) ≈1.67V
(c) ≈1.47V
(d) ≈1.37V
Correct Answer:
≈1.67V
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The current in the coil of inductance 5H decreases at the rate of 2 A/s
- Two wires of the same dimensions but resistivities p1 and p2 are connected in series
- A rectangular coil of length 0.12 m and width 0.1 m having 50 turns of wire
- The coherence of two light sources means that the light waves emitted have
- A body is under stress F and has Young’s modulus Y, then the energy
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The current in the coil of inductance 5H decreases at the rate of 2 A/s
- Two wires of the same dimensions but resistivities p1 and p2 are connected in series
- A rectangular coil of length 0.12 m and width 0.1 m having 50 turns of wire
- The coherence of two light sources means that the light waves emitted have
- A body is under stress F and has Young’s modulus Y, then the energy
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply