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Two Carnot engine A and B are operated in series. The engine A receives that heat from the source at temperature T₁ and rejects the heat to the sink at temperature T. The second engine B receives the heat at temperature T and rejects to its sink at temperature T₂. For what value of T the efficiencies of the two engines are equal?
Options
(a) T₁ + T₂ / 2
(b) T₁ – T₂ / 2
(c) T₁ T₂
(d) √(T₁ T₂)
Correct Answer:
√(T₁ T₂)
Explanation:
Efficiency of engine A, ?￢ﾂﾁ = 1 – T / T₁,
Efficiency of engine B, ?￢ﾂﾂ = 1 – T₂ / T,
Here, ?￢ﾂﾁ = ?￢ﾂﾂ
T / T₁ = T₂ / T ⇒ T = √T₁T₂
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Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two nuclei have their mass numbers into the ratio of 1:3
- A voltmeter of range 2 V and resistance 300Ω cannot be converted into ammeter
- Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state
- A scooter is going round a circular road of radius 100 m at a speed of 10m/s
- Laser beams are used to measure long distance because
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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