| ⇦ | 
| ⇨ |
Two Carnot engine A and B are operated in series. The engine A receives that heat from the source at temperature T₁ and rejects the heat to the sink at temperature T. The second engine B receives the heat at temperature T and rejects to its sink at temperature T₂. For what value of T the efficiencies of the two engines are equal?
Options
(a) T₁ + T₂ / 2
(b) T₁ – T₂ / 2
(c) T₁ T₂
(d) √(T₁ T₂)
Correct Answer:
√(T₁ T₂)
Explanation:
Efficiency of engine A, ?￢ﾂﾁ = 1 – T / T₁,
Efficiency of engine B, ?￢ﾂﾂ = 1 – T₂ / T,
Here, ?￢ﾂﾁ = ?￢ﾂﾂ
T / T₁ = T₂ / T ⇒ T = √T₁T₂
Related Questions:
- A nucleus at rest splits into two nuclear parts having radii in the ratio 1:2.
- A proton beam enters a magnetic field of 10⁻⁴ Wb/m² normally. If the specific charge
- A transformer of 100% efficiency has 200 turns in the primary coil and 40000 turns
- The young’s modulus of steel is twice that of brass. Two wires of same length
- A calorimeter contains 0.2 kg of water at 30° C. 0.1kg of water at
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply