| ⇦ |
| ⇨ |
A proton beam enters a magnetic field of 10⁻⁴ Wb/m² normally. If the specific charge of the proton is 10¹¹ C/kg and its velocity is 10⁹ m/s, then the radius of the circle described will be
Options
(a) 100 m
(b) 0.1 m
(c) 1 m
(d) 10 m
Correct Answer:
100 m
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Application of Bernoulli’s theorem can be seen in
- The refracting angle of a prism is A and refractive index of the material of the prism
- The area of cross-section of a steel wire (Y=2.0×10¹¹ N/m²) is 0.1 cm².
- A ball of mass 2 kg and another of mass 4 kg are dropped together from
- Which one of the following is not a unit of young’s modulus?
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Application of Bernoulli’s theorem can be seen in
- The refracting angle of a prism is A and refractive index of the material of the prism
- The area of cross-section of a steel wire (Y=2.0×10¹¹ N/m²) is 0.1 cm².
- A ball of mass 2 kg and another of mass 4 kg are dropped together from
- Which one of the following is not a unit of young’s modulus?
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply