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Three capacitors each of capacitance C and of breakdown voltage V are joined in series. The capacitance and breakdown voltage of the combination will be
Options
(a) 3C, V/3
(b) C/3, 3V
(c) 3C, 3V
(d) C/3, V/3
Correct Answer:
C/3, 3V
Explanation:
In series combination of capacitors Veff = V + V + V = 3V
1/Ceff = 1/C + 1/C + 1/C
Ceff = C / 3
Thus, the capacitance and breakdown voltage of the combination will be C/3 and 3V.
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
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