⇦ | ⇨ |
The young’s modulus of steel is twice that of brass. Two wires of same length and of same area of cross section, one of steel and another of brass are suspended from the same roof. If we want the lower ends of the wires to be at the same level, then the weights addes to the steel and brass wires must be in the ratio of
Options
(a) -04:01:00
(b) -01:01:00
(c) -01:02:00
(d) -02:01:00
Correct Answer:
-02:01:00
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A particle of mass ‘m’ is kept at rest at a height 3R from the surface of earth
- An electric dipole of dipole moment p is placed in a uniform external electric field
- A student performs an experiment to determine the Young’s modulus of a wire
- The coefficient of mutual inductance of two coils is 6 mH. If the current flowing
- The radius of orbit of a planet is two times that of the earth. The time period
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle of mass ‘m’ is kept at rest at a height 3R from the surface of earth
- An electric dipole of dipole moment p is placed in a uniform external electric field
- A student performs an experiment to determine the Young’s modulus of a wire
- The coefficient of mutual inductance of two coils is 6 mH. If the current flowing
- The radius of orbit of a planet is two times that of the earth. The time period
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply