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The wavelength of first line of Balmer series is 6563Å. The wavelength of first line of Lyman series will be
Options
(a) 1215.4Å
(b) 2500Å
(c) 7500Å
(d) 600Å
Correct Answer:
1215.4Å
Explanation:
λ(ʟyman) / λ(вalmer) = [(1/2²) – (1/3²)] / [(1/1²) – (1/2)²] = 5 / 27
λ(ʟyman) = (5 / 27) × λ(вalmer) = (5 / 27) × 6563 = 1215.4 Å
Related Questions: - Which of the following measurement is most precise?
- A galvanometer is converted into an ammeter by connecting
- In refraction, light waves are bent on passing from one medium to the second medium
- In an ammeter, 0.2% of main current passes through the galvanometer
- Choose the correct statement
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following measurement is most precise?
- A galvanometer is converted into an ammeter by connecting
- In refraction, light waves are bent on passing from one medium to the second medium
- In an ammeter, 0.2% of main current passes through the galvanometer
- Choose the correct statement
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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