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The wavelength of first line of Balmer series is 6563Å. The wavelength of first line of Lyman series will be
Options
(a) 1215.4Å
(b) 2500Å
(c) 7500Å
(d) 600Å
Correct Answer:
1215.4Å
Explanation:
λ(ʟyman) / λ(вalmer) = [(1/2²) – (1/3²)] / [(1/1²) – (1/2)²] = 5 / 27
λ(ʟyman) = (5 / 27) × λ(вalmer) = (5 / 27) × 6563 = 1215.4 Å
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Maximum velocity of the photoelectrons emitted by a metal surface is 1.2×10⁶ ms⁻¹.
- A solid cylinder of mass M and radius R rolls without slipping down and inclined plane
- In the given figure, a diode D is connected to an external resistance R=100 Ω
- If the volume of a block of aluminium is decreased by 1%, the pressure
- A galvanometer having internal resistance 10Ω requires 0.01 A for a full scale
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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