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The wavelength of first line of Balmer series is 6563Å. The wavelength of first line of Lyman series will be
Options
(a) 1215.4Å
(b) 2500Å
(c) 7500Å
(d) 600Å
Correct Answer:
1215.4Å
Explanation:
λ(ʟyman) / λ(вalmer) = [(1/2²) – (1/3²)] / [(1/1²) – (1/2)²] = 5 / 27
λ(ʟyman) = (5 / 27) × λ(вalmer) = (5 / 27) × 6563 = 1215.4 Å
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- The self induced e.m.f. in a 0.1 H coil when the current in it is changing
- An electric dipole of dipole moment p is aligned parallel to a uniform electric field E
- A body A experiences perfectly elastic collision with a stationary body B
- The original temperature of a black body is 727⁰C. The temperature at which this black
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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