| ⇦ | 
| ⇨ |
The velocity of molecules of a gas at temperature 120 K is v. At what temperature will the velocity be 2v?
Options
(a) 120 K
(b) 240 K
(c) 480 K
(d) 1120 K
Correct Answer:
480 K
Explanation:
[ʋ(rms)]² ∝ absolute temperature
[ʋ₂ / ʋ₁]² = T₂ / T₁ ⇒ (2V / V)² = T₂ / 120
.·. T₂ = 120 × 4 = 480 K
Related Questions: - Point masses m₁ and m₂ are placed at the opposite ends of a rigid rod of length L,
- A parallel beam of fast moving electrons is incident normally on a narrow slit.
- In cyclotron, for a given magnet, radius of the semicircle traced by positive ion
- A thin semicircular conducting ring (PQR) of radius r is falling with its plane
- The rest mass of a body is m1. It moves with a velocity of 0.6c, then its relativistic
Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Point masses m₁ and m₂ are placed at the opposite ends of a rigid rod of length L,
- A parallel beam of fast moving electrons is incident normally on a narrow slit.
- In cyclotron, for a given magnet, radius of the semicircle traced by positive ion
- A thin semicircular conducting ring (PQR) of radius r is falling with its plane
- The rest mass of a body is m1. It moves with a velocity of 0.6c, then its relativistic
Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply