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The velocity of a particle performing simple harmonic motion, when it passes through its mean position is
Options
(a) Infinity
(b) Zero
(c) Minimum
(d) Maximum
Correct Answer:
Maximum
Explanation:
ν = ω √(a² – y²), At mean position y = 0
ν = ωa = This is the maximum velocity.
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A Carnot engine, having an efficiency of η=1/10 as heat engine, is used
- Two beams of light having intensities I and 4I interfere to produce a fringe pattern
- A boy playing on the roof of a 10m high building throws a ball with a speed
- Which of the following is or the property of a cathode ray
- The maximum kinetic energy of emitted electrons in a photoelectric effect
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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At mean position x=0
Therefore v=w(√a^2-0^2)
Therefore v=w(√a^2)=aw
Vmax=aw