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The velocity of a particle performing simple harmonic motion, when it passes through its mean position is
Options
(a) Infinity
(b) Zero
(c) Minimum
(d) Maximum
Correct Answer:
Maximum
Explanation:
ν = ω √(a² – y²), At mean position y = 0
ν = ωa = This is the maximum velocity.
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An ideal gas is expanding such that PT²=constant. The coefficient of volume
- Velocities of sound measured in hydrogen and oxygen gas at a given temperature
- A cricket ball of mass 250 g collides with a bat with velocity 10 m/s
- A radioactive sample S₁ having an activity of 5 μCi has twice the number of nuclei
- A spring of spring constant 5 x 10³ N/m is stretched initially by 5 cm
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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At mean position x=0
Therefore v=w(√a^2-0^2)
Therefore v=w(√a^2)=aw
Vmax=aw