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The velocity of a particle performing simple harmonic motion, when it passes through its mean position is
Options
(a) Infinity
(b) Zero
(c) Minimum
(d) Maximum
Correct Answer:
Maximum
Explanation:
ν = ω √(a² – y²), At mean position y = 0
ν = ωa = This is the maximum velocity.
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle moving along a straight line OX.At a time (in second ) the distance
- A circuit contains an ammeter, a battery of 30 V and a resistance 40.8 ohm
- When a radioactive substance emits an ∝ particle, its position in the periodic table
- A capacitor is charged to 200 volt. It has a charge of 0.1 coulomb.
- Which of the following is not a thermodynamical coordinate?
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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At mean position x=0
Therefore v=w(√a^2-0^2)
Therefore v=w(√a^2)=aw
Vmax=aw