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The velocity of a particle performing simple harmonic motion, when it passes through its mean position is
Options
(a) Infinity
(b) Zero
(c) Minimum
(d) Maximum
Correct Answer:
Maximum
Explanation:
ν = ω √(a² – y²), At mean position y = 0
ν = ωa = This is the maximum velocity.
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- The wavelength λₑ of an electron and λₚ of a photon are of same energy E are related by
- What is the voltage gain in a common-emiiter amplifier, when input resistance is 4 Ω
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- If a nucleus ᴢXᴬ emits 9α and 5β-particles, then the ratio of total protons and neutrons
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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At mean position x=0
Therefore v=w(√a^2-0^2)
Therefore v=w(√a^2)=aw
Vmax=aw