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The velocity of a particle performing simple harmonic motion, when it passes through its mean position is
Options
(a) Infinity
(b) Zero
(c) Minimum
(d) Maximum
Correct Answer:
Maximum
Explanation:
ν = ω √(a² – y²), At mean position y = 0
ν = ωa = This is the maximum velocity.
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Topics: Oscillations
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Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is an example of ideal black body?
- When three identical bulbs of 60 W-200 V rating are connected in series to a 200 V
- A p-n photodiode is fabricated from a semiconductor with a band gap of 2.5 eV.
- The induced emf in a coil of 10 H inductance in which current varies
- Laser beams are used to measure long distance because
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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At mean position x=0
Therefore v=w(√a^2-0^2)
Therefore v=w(√a^2)=aw
Vmax=aw