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The velocity of a particle performing simple harmonic motion, when it passes through its mean position is
Options
(a) Infinity
(b) Zero
(c) Minimum
(d) Maximum
Correct Answer:
Maximum
Explanation:
ν = ω √(a² – y²), At mean position y = 0
ν = ωa = This is the maximum velocity.
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A coil of N turns and mean cross-sectional area A is rotating with uniform angular
- The work done in which of the following processes is equal to the change in internal energy
- Two bulbs 60 W and 100 W designed for voltage 220 V are connected in series
- In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency
- The sun light reaches us as white and not as its components because
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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At mean position x=0
Therefore v=w(√a^2-0^2)
Therefore v=w(√a^2)=aw
Vmax=aw