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The velocity of a particle performing simple harmonic motion, when it passes through its mean position is
Options
(a) Infinity
(b) Zero
(c) Minimum
(d) Maximum
Correct Answer:
Maximum
Explanation:
ν = ω √(a² – y²), At mean position y = 0
ν = ωa = This is the maximum velocity.
Related Questions: - A wire in the form of a circular loop of one turn, carrying a current, produces
- which of the following statement is false for the properties of electromagnetic waves?
- When a light beam of frequency v is incident on a metal surface,
- On a frictionless surface, a block of mass M moving at speed v collides elastically
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A wire in the form of a circular loop of one turn, carrying a current, produces
- which of the following statement is false for the properties of electromagnetic waves?
- When a light beam of frequency v is incident on a metal surface,
- On a frictionless surface, a block of mass M moving at speed v collides elastically
- The respective speeds of the molecules are 1,2,3,4 and 5 km/s.
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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At mean position x=0
Therefore v=w(√a^2-0^2)
Therefore v=w(√a^2)=aw
Vmax=aw