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The velocity of a particle performing simple harmonic motion, when it passes through its mean position is
Options
(a) Infinity
(b) Zero
(c) Minimum
(d) Maximum
Correct Answer:
Maximum
Explanation:
ν = ω √(a² – y²), At mean position y = 0
ν = ωa = This is the maximum velocity.
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If A=3i+4j and B=7i+24j the vector having the same magnitude as B and parallel to A is
- Height of geostationary satellite is
- The equations of motion of a projectile are given by x=36 t metre and 2y=96t-9.8t²
- The velocity of image when object and mirror both are moving towards each other
- A wire elongates by l mm when a load W is hanged from it. If the wire goes over
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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At mean position x=0
Therefore v=w(√a^2-0^2)
Therefore v=w(√a^2)=aw
Vmax=aw