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The velocity of a particle performing simple harmonic motion, when it passes through its mean position is
Options
(a) Infinity
(b) Zero
(c) Minimum
(d) Maximum
Correct Answer:
Maximum
Explanation:
ν = ω √(a² – y²), At mean position y = 0
ν = ωa = This is the maximum velocity.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The magnetic flux linked with a circuit of resistance 100Ω increases from 10 to 60 Wb.
- Two spherical conductors A and B of radii 1 mm and 2 mm are separated by a distance
- A particle has initial velocity (2i⃗+3j⃗) and acceleration (0.3i⃗+0.2j⃗). The magnitude
- What are the unit of K = 1 / (4 π ?￢ﾂﾒ)
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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At mean position x=0
Therefore v=w(√a^2-0^2)
Therefore v=w(√a^2)=aw
Vmax=aw