| ⇦ | 
| ⇨ |
The velocity of a particle performing simple harmonic motion, when it passes through its mean position is
Options
(a) Infinity
(b) Zero
(c) Minimum
(d) Maximum
Correct Answer:
Maximum
Explanation:
ν = ω √(a² – y²), At mean position y = 0
ν = ωa = This is the maximum velocity.
Related Questions: - Which one of the following bonds produces a solid that reflects light in the visible region
- Characteristic X-rays are produced due to
- A circular disc of radius 0.2 meter is placed in a uniform magnetic field of induction
- Bohr’s postulates quantizes
- A piece of iron is heated in a flame. It first comes dull red then becomes reddish
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which one of the following bonds produces a solid that reflects light in the visible region
- Characteristic X-rays are produced due to
- A circular disc of radius 0.2 meter is placed in a uniform magnetic field of induction
- Bohr’s postulates quantizes
- A piece of iron is heated in a flame. It first comes dull red then becomes reddish
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
At mean position x=0
Therefore v=w(√a^2-0^2)
Therefore v=w(√a^2)=aw
Vmax=aw