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The velocity of a particle performing simple harmonic motion, when it passes through its mean position is
Options
(a) Infinity
(b) Zero
(c) Minimum
(d) Maximum
Correct Answer:
Maximum
Explanation:
ν = ω √(a² – y²), At mean position y = 0
ν = ωa = This is the maximum velocity.
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A wire of length 1 m is moving at a speed of 2 ms⁻¹ perpendicular to its length
- The current gain of a transistor in common base configuration is 0.96.
- Water rises to a height h in capillary tube. If the length of capillary tube above
- The wave described by y = 0.25 sin (10 2πx – 2πt), where x and y are in meters
- A deutron is bombarded on ₈O¹⁶ nucleus and α-particle is emitted. The product nucleus is
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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At mean position x=0
Therefore v=w(√a^2-0^2)
Therefore v=w(√a^2)=aw
Vmax=aw