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The velocity of a particle performing simple harmonic motion, when it passes through its mean position is
Options
(a) Infinity
(b) Zero
(c) Minimum
(d) Maximum
Correct Answer:
Maximum
Explanation:
ν = ω √(a² – y²), At mean position y = 0
ν = ωa = This is the maximum velocity.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The refracting angle of a prism is A and refractive index of the material of the prism
- An ideal heat engine works between temperature T₁=500 K and T₂=375 K.
- The earth is assumed to be a sphere of radius R. A platform is arranged at a height R
- A body takes 5 minute for cooling from 50⁰C to 40⁰C. Its temperature
- A photon of wavelength 300nm interacts with a stationary hydrogen atom in ground
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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At mean position x=0
Therefore v=w(√a^2-0^2)
Therefore v=w(√a^2)=aw
Vmax=aw