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The velocity of a particle performing simple harmonic motion, when it passes through its mean position is
Options
(a) Infinity
(b) Zero
(c) Minimum
(d) Maximum
Correct Answer:
Maximum
Explanation:
ν = ω √(a² – y²), At mean position y = 0
ν = ωa = This is the maximum velocity.
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If a magnetic substance is brought near the north or the south pole of a bar magnet
- When a ceiling fan is switched on, it makes 10 revolutions in the first 3s
- A proton and helium nucleus are shot into a magnetic field at right angles to the field
- An inclined plane of length 5.60m making an angle of 45⁰ with the horizontal is placed
- A perfect gas at 27° C is heated at constant pressure to 327° C. If original volume of gas
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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At mean position x=0
Therefore v=w(√a^2-0^2)
Therefore v=w(√a^2)=aw
Vmax=aw