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The velocity of a particle performing simple harmonic motion, when it passes through its mean position is
Options
(a) Infinity
(b) Zero
(c) Minimum
(d) Maximum
Correct Answer:
Maximum
Explanation:
ν = ω √(a² – y²), At mean position y = 0
ν = ωa = This is the maximum velocity.
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(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If a charge in current of 0.01 A in one coil produces a change in magnetic flux
- Three masses are placed on the x-axis : 300 g at origin, 500 g at x = 40 cm
- The velocity of image when object and mirror both are moving towards each other
- The velocity of sound is V, in air. If the density of air is increased to four times
- The valence band and the conductance band of a solid overlap at low temperature
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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At mean position x=0
Therefore v=w(√a^2-0^2)
Therefore v=w(√a^2)=aw
Vmax=aw