| ⇦ |
| ⇨ |
In an interference experiment, third bright fringe is obtained at a point on the screen with a light of 700 nm. What should be the wavelength of the light source in order to obtain 5th bright firnge at the same point?
Options
(a) 500 nm
(b) 630 nm
(c) 750 nm
(d) 420 nm
Correct Answer:
420 nm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Unit of reduction factor is
- Two thin long conductors seprated by a distance d carry currents
- Light is emitted when
- The net electric force on a charge of +3μC at the mid-point on the line joining two
- The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Unit of reduction factor is
- Two thin long conductors seprated by a distance d carry currents
- Light is emitted when
- The net electric force on a charge of +3μC at the mid-point on the line joining two
- The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply