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In an interference experiment, third bright fringe is obtained at a point on the screen with a light of 700 nm. What should be the wavelength of the light source in order to obtain 5th bright firnge at the same point?
Options
(a) 500 nm
(b) 630 nm
(c) 750 nm
(d) 420 nm
Correct Answer:
420 nm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The radius of germanium nuclide is measured to be twice the radius of ₄⁹Be.
- The electric field part of an electromagnetic wave in a medium is represented by
- An electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into
- A p-n photodiode is fabricated from a semiconductor with a band gap of 2.5 eV.
- Consider a uniform square plate of side ɑ and mass m. The moment of inertia
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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