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The value of workdone for rotating a magnet of magnetic moment M by an angle θ in external magnetic field H is given by
Options
(a) MH cos θ
(b) 2MH sin²(θ/2)
(c) MH sin θ
(d) MH (1-sin²θ)
Correct Answer:
MH cos θ
Explanation:
MH (1 – cos θ) = work done
.·. W = MH [1 – 1 + 2 sin² (θ / 2)] = 2MH sin² (θ / 2)
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of minimum wavelengths of Lyman and Balmer series will be
- The angular momentum of an electron is J. The magnitude of the magnetic moment
- A proton and an alpha particle both enter a region of uniform magnetic field B,
- A bar magnet of pole strength 10 A-m is cut into two equal parts breadthwise.
- In some region, gravitational field is zero. The gravitational potential
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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B is the right option