| ⇦ | 
| ⇨ |
The value of workdone for rotating a magnet of magnetic moment M by an angle θ in external magnetic field H is given by
Options
(a) MH cos θ
(b) 2MH sin²(θ/2)
(c) MH sin θ
(d) MH (1-sin²θ)
Correct Answer:
MH cos θ
Explanation:
MH (1 – cos θ) = work done
.·. W = MH [1 – 1 + 2 sin² (θ / 2)] = 2MH sin² (θ / 2)
Related Questions: - A ship A is moving westwards with a speed of 10 km/h .The time after
- Two radioactive materials X₁ and X₂ have decay constants 5λ and λ respectively
- Water drops fall from a top on the floor 5 m below at regular intervals
- A parallel plate condenser with a dielectric of dielectric constant K between the plates
- Young’s modulus of the material of a wire is 18×10¹¹ dyne cm⁻².its value in SI is
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A ship A is moving westwards with a speed of 10 km/h .The time after
- Two radioactive materials X₁ and X₂ have decay constants 5λ and λ respectively
- Water drops fall from a top on the floor 5 m below at regular intervals
- A parallel plate condenser with a dielectric of dielectric constant K between the plates
- Young’s modulus of the material of a wire is 18×10¹¹ dyne cm⁻².its value in SI is
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
B is the right option