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The two ends of a rod of length L and a uniform cross-sectional area A are kept at two temperatures T₁ and T₂ (T₁ > T₂). The rate of heat transfer, dQ/dt through the rod in a steady state is given by:
Options
(a) dQ/dt = k(T₁ – T₂) / LA
(b) dQ/dt = kLA (T₁ – T₂)
(c) dQ/dt = kA (T₁ – T₂) / L
(d) dQ/dt = kL (T₁ – T₂) / A
Correct Answer:
dQ/dt = kA (T₁ – T₂) / L
Explanation:
dQ / dt = kA (T₁ -T₂) / L
[(T₁ -T₂) is the temperature difference]
Related Questions: - A particle of mass 1.96×10⁻¹⁵ kg is kept in equilibrium between two horizontal metal
- In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series
- A metal conductor of length 1m rotates vertically about one of its ends at angular
- The limiting angle of incidence for an optical ray that can be transmitted
- Huygen’s wave theory could not explain
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle of mass 1.96×10⁻¹⁵ kg is kept in equilibrium between two horizontal metal
- In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series
- A metal conductor of length 1m rotates vertically about one of its ends at angular
- The limiting angle of incidence for an optical ray that can be transmitted
- Huygen’s wave theory could not explain
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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