| ⇦ |
| ⇨ |
A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 radian per second. If the horizontal component of earth’s magnetic field is 0.2×10⁻⁴ T, then the e.m.f. developed between the two ends of the conductor is
Options
(a) 5 μV
(b) 50 mV
(c) 5 mV
(d) 50 μV
Correct Answer:
50 mV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A ship A is moving westwards with a speed of 10 km/h and a ship B 100 km
- Two parallel metal plates having charges +Q and -Q face each other at a certain
- Starting from the origin, a body oscillates simple harmonically with a period of 2s
- An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by
- A bar magnet of pole strength 10 A-m is cut into two equal parts breadthwise.
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A ship A is moving westwards with a speed of 10 km/h and a ship B 100 km
- Two parallel metal plates having charges +Q and -Q face each other at a certain
- Starting from the origin, a body oscillates simple harmonically with a period of 2s
- An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by
- A bar magnet of pole strength 10 A-m is cut into two equal parts breadthwise.
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply