| ⇦ |
| ⇨ |
A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 radian per second. If the horizontal component of earth’s magnetic field is 0.2×10⁻⁴ T, then the e.m.f. developed between the two ends of the conductor is
Options
(a) 5 μV
(b) 50 mV
(c) 5 mV
(d) 50 μV
Correct Answer:
50 mV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Electric field at a point of distance r from a uniformly charged wire of infinite
- A current I ampere flows along the inner conductor of a co-axial cable and returns
- A particle moves a distance x in time t according to equation x = (t + 5)⁻¹
- The ratio of longest wavelength corresponding to Lyman and Blamer series
- Which component of electromagnetic spectrum have maximum wavelength?
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Electric field at a point of distance r from a uniformly charged wire of infinite
- A current I ampere flows along the inner conductor of a co-axial cable and returns
- A particle moves a distance x in time t according to equation x = (t + 5)⁻¹
- The ratio of longest wavelength corresponding to Lyman and Blamer series
- Which component of electromagnetic spectrum have maximum wavelength?
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply