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The total energy of an electron in the first excited state of hydrogen atom is about -3.4 eV. Its kinetic energy in this state is
Options
(a) 3.4 eV
(b) 6.8 eV
(c) -3.4 eV
(d) -6.8 eV
Correct Answer:
3.4 eV
Explanation:
KE. = |(1/2) P.E.|
But P.E. is negavite
.·. Total energy = |(1/2) P.E.| – P.E. = – P.E. / 2 = – 3.4 eV
.·. K.E. = + 3.4 eV
Related Questions: - An electron of mass Mₑ, initially at rest, moves through a certain distance in a uniform
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electron of mass Mₑ, initially at rest, moves through a certain distance in a uniform
- An electron in hydrogen atom makes a transition n₁ → n₂
- If the red light is replaced by blue light illuminating the object in a microscope
- If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is
- A rectangular copper coil is placed in a uniform magnetic field of induction 40 mT
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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