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The total energy of an electron in the first excited state of hydrogen atom is about -3.4 eV. Its kinetic energy in this state is
Options
(a) 3.4 eV
(b) 6.8 eV
(c) -3.4 eV
(d) -6.8 eV
Correct Answer:
3.4 eV
Explanation:
KE. = |(1/2) P.E.|
But P.E. is negavite
.·. Total energy = |(1/2) P.E.| – P.E. = – P.E. / 2 = – 3.4 eV
.·. K.E. = + 3.4 eV
Related Questions: - A 2 kg mass starts from rest on an inclined smooth surface with inclination
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A 2 kg mass starts from rest on an inclined smooth surface with inclination
- The electron of a hydrogen atom revolves round the proton in a circular
- The transition from the state 3 n = 3 to n = 1 in a hydrogen like atom results
- A beam of light consisting of red, green and blue colours is incident on a right
- Angle of minimum deviation for a prism of reractive index 1.5 equal to the angle
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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