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The total energy of an electron in the first excited state of hydrogen atom is about -3.4 eV. Its kinetic energy in this state is
Options
(a) 3.4 eV
(b) 6.8 eV
(c) -3.4 eV
(d) -6.8 eV
Correct Answer:
3.4 eV
Explanation:
KE. = |(1/2) P.E.|
But P.E. is negavite
.·. Total energy = |(1/2) P.E.| – P.E. = – P.E. / 2 = – 3.4 eV
.·. K.E. = + 3.4 eV
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle is released from rest from a tower of height h, i.e,t₁ : t₂ : t₃ is
- The displacement of an object attached to a spring and executing simple harmonic
- A common emitter amplifier has a voltage gain of 50, an input impedance of 100Ω
- A ray enters a glass sphere of refractive index μ=√3 at an angle of incidence of 60⁰
- A wind with speed 40 m/s blows parallel to the roof of a house. The area of the roof
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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