| ⇦ |
| ⇨ |
A 2 kg mass starts from rest on an inclined smooth surface with inclination 30° and length 2 m. How much will it travel before coming to rest on a frictional surface with frictional coefficient of 0.25?
Options
(a) 4 m
(b) 6 m
(c) 8 m
(d) 2 m
Correct Answer:
4 m
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The rms current in an AC circuit is 2 A. If the wattless current be √3 A,
- A thin ring of radius R meter has charge q coulomb uniformly spread on it
- Two point charges +2 coulomb and +10 coulomb repel each other with a force of 12 N.
- A parallel plate air capacitor is charged to a potential difference of V volts.
- Energy stored in the coil of a self inductance 40 mH carrying a steady current of 2A
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The rms current in an AC circuit is 2 A. If the wattless current be √3 A,
- A thin ring of radius R meter has charge q coulomb uniformly spread on it
- Two point charges +2 coulomb and +10 coulomb repel each other with a force of 12 N.
- A parallel plate air capacitor is charged to a potential difference of V volts.
- Energy stored in the coil of a self inductance 40 mH carrying a steady current of 2A
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

v2=u2+2gsin30
v=root20
S=v2/2(mu)g
S=20/2*0.25*10
S=4m