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The time period of a simple pendulum in a lift descending with constant acceleration g is
Options
(a) T=2π√l/g
(b) T=2π√l/2g
(c) zero
(d) Infinite
Correct Answer:
Infinite
Explanation:
When the lift falls freely under gravity, effective ‘g’ for pendulum in the lift = zero.
T = 2π √(l/g) = 2π√(l/o) = Infinite.
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle moving in a straight line with uniform acceleration is observed
- In a common emitter (CE) amplifier having a voltage gain G, the transistor
- Monochromatic light of wavelength 667 nm is produced by a helium neon laser
- A parallel plate capacitor with air between the plates has a capacitance of 9 pF.
- The wave function (in SI unit) for a light wave is given as Ψ(x,t)= 10³ sin π
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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