The threshold frequency for a photosensitive metal is 3.3 x 10¹⁴ Hz.

⇦

⇨

The threshold frequency for a photosensitive metal is 3.3 x 10¹⁴ Hz. If light of frequency 8.2 x 10¹⁴ Hz incident on this metal, the cut-off voltage for the photoelectric emission is nearly

Options

(a) 2 V
(b) 3 V
(c) 5 V
(d) 1 V

Correct Answer:

2 V

Explanation:

K.E = hv – hvₜₕ = eV₀ ( V₀ = cut off voltage)
V₀ = h/e (8.2 x 10¹⁴ – 3.3 x 10¹⁴)
= 6.6 x 10⁻³⁴ x 4.9 x 10¹⁴ / 1.6 x 10⁻¹⁹ = 2 V

Related Questions:

1. Bohr’s postulates quantizes
2. Slope of PV and V for an isobaric process will be
3. In a uniform circular motion, work done in one complete rotation is
4. A body of mass 4 kg is accelerated upon by a constant force travels
5. When a mass M is attached to a spring of force constant K,

Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends