| ⇦ | 
| ⇨ |
The threshold frequency for a photosensitive metal is 3.3 x 10¹⁴ Hz. If light of frequency 8.2 x 10¹⁴ Hz incident on this metal, the cut-off voltage for the photoelectric emission is nearly
Options
(a) 2 V
(b) 3 V
(c) 5 V
(d) 1 V
Correct Answer:
2 V
Explanation:
K.E = hv – hvₜₕ = eV₀ ( V₀ = cut off voltage)
V₀ = h/e (8.2 x 10¹⁴ – 3.3 x 10¹⁴)
= 6.6 x 10⁻³⁴ x 4.9 x 10¹⁴ / 1.6 x 10⁻¹⁹ = 2 V
Related Questions: - The total energy of an electron in the first excited state of hydrogen atom
- Which of the following physical quantities has neither dimensions nor unit
- If a magnetic substance is brought near the north or the south pole of a bar magnet
- In an interference experiment, third bright fringe is obtained at a point
- Which one of the following statements is not correct in case of a semiconductor?
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The total energy of an electron in the first excited state of hydrogen atom
- Which of the following physical quantities has neither dimensions nor unit
- If a magnetic substance is brought near the north or the south pole of a bar magnet
- In an interference experiment, third bright fringe is obtained at a point
- Which one of the following statements is not correct in case of a semiconductor?
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply