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The surface tension of soap solution is 0.03 N/m. The work done in blowing to form a soap bubble of surface area 40 cm², in joules is
Options
(a) 1.2×10⁻⁴
(b) 2.4×10⁻⁴
(c) 12×10⁻⁴
(d) 24×10⁻⁴
Correct Answer:
2.4×10⁻⁴
Explanation:
Given: Surface tension of a soap solution,
T = 0.03 N/m
Surface area, A = 40 cm² = 40 x 10⁻⁴ m²
Since the soap has two surfaces,
.·. Work done, W = T x 24
= 0.03 x 2 40 x 10⁻⁴ = 2.4 x 10⁻⁴J
Related Questions: - A particle is moving with a uniform velocity along a straight line path
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Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle is moving with a uniform velocity along a straight line path
- Radius of a soap bubble is increased from R to 2R. Work done in this process
- The speed of light in media M₁ and M₂ are 1.5×10⁸ ms⁻¹ and 2×10⁸ ms⁻¹ respectively.
- A block of mass 10 kg is moving in X-direction with a constant speed of 10 ms⁻¹
- The work done in which of the following processes is equal to the change in internal energy
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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