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**Radius of a soap bubble is increased from R to 2R. Work done in this process in terms of surface tension S is **

### Options

(a) 24 πR²S

(b) 48 πR²S

(c) 12 πR²S

(d) 36 πR²S

### Correct Answer:

24 πR²S

### Explanation:

Work done = 2 x S x Change in surface area

W = 2 x S x 4π (R₂² – R₁²)

Given: R₂ = 2R, R₁ = R = 8S π (4R² – R²) = 24 πR²S.

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Topics: Properties of Bulk Matter
(130)

Subject: Physics
(2479)

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