⇦ | ⇨ |
The surface tension of soap solution is 0.03 N/m. The work done in blowing to form a soap bubble of surface area 40 cm², in joules is
Options
(a) 1.2×10⁻⁴
(b) 2.4×10⁻⁴
(c) 12×10⁻⁴
(d) 24×10⁻⁴
Correct Answer:
2.4×10⁻⁴
Explanation:
Given: Surface tension of a soap solution,
T = 0.03 N/m
Surface area, A = 40 cm² = 40 x 10⁻⁴ m²
Since the soap has two surfaces,
.·. Work done, W = T x 24
= 0.03 x 2 40 x 10⁻⁴ = 2.4 x 10⁻⁴J
Related Questions: - The ionisation potential of hydrogen-atom is -13.6 eV. An electron in the groundstate
- On bombarding U²³⁵ by slow neutron, 200 MeV energy is released. If the power output
- Surface tension of a solution is 30 x 10⁻² N/m. The radius of the soap bubble is 5 cm
- Which of the following is an example of ideal black body?
- An air core solenoid has 1000 turns and is one meter long. Its cross sectional area
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ionisation potential of hydrogen-atom is -13.6 eV. An electron in the groundstate
- On bombarding U²³⁵ by slow neutron, 200 MeV energy is released. If the power output
- Surface tension of a solution is 30 x 10⁻² N/m. The radius of the soap bubble is 5 cm
- Which of the following is an example of ideal black body?
- An air core solenoid has 1000 turns and is one meter long. Its cross sectional area
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply