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A hemispherical bowl of radius R is rotating about its axis of symmetry which is kept vertical.A small ball kept in the bowl rotates with the bowl without sliiping on its surface.If the surface of the bowl is smooth and the angle made by the radius through the ball with the vertical is α.Find the angular speed at which the bowl is rotating.
Options
(a) √(g / R sinα)
(b) √(g / R cosα)
(c) g√(1 / R cosα)
(d) g√(1 / R sinα)
Correct Answer:
√(g / R cosα)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Wires A and B are made from the same material. A has twice the diameter and three times
- Two spheres of mass m and M are situated in air and the gravitational force
- A carnot’s engine operates with source at 127° C and sink at 27°C
- Three unequal resistors in parallel are equivalent to a resistance 1 Ω.
- The angle between the dipole moment and electric field at any point on the equatoria
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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