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A hemispherical bowl of radius R is rotating about its axis of symmetry which is kept vertical.A small ball kept in the bowl rotates with the bowl without sliiping on its surface.If the surface of the bowl is smooth and the angle made by the radius through the ball with the vertical is α.Find the angular speed at which the bowl is rotating.
Options
(a) √(g / R sinα)
(b) √(g / R cosα)
(c) g√(1 / R cosα)
(d) g√(1 / R sinα)
Correct Answer:
√(g / R cosα)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of the weight of a man in a stationary lift and when it is moving downwards
- A pure semiconductor behaves slightly as a conductor at
- A planet in a distinct solar system is 10 times more massive than the earth
- A heavy stone hanging from a massless string of length 15 m is projected
- The equiconvex lens has focal length f. If it is cut perpendicular to the principal
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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