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The string of a pendulum is horizontal.The mass of bob attached to it is m.Now, the string is released.The tension in the string in the lowest position is
Options
(a) mg
(b) 2 mg
(c) 3 mg
(d) 4 mg
Correct Answer:
3 mg
Explanation:
When string is released, then according to conservation of energy,
(1/2) mv² = mgh
v² = 2gh = 2gR
Now, when it is at the bottom,
T – mg cos 0² = mv²/R
or T – mg = (m/R)(2gR)
T = mg + 2mg = 3mg.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Length of a conductor is 50 cm radius of cross section 0.1 cm and resistivity
- In the elastic collision of objects
- What is the voltage gain in a common-emiiter amplifier, when input resistance is 4 Ω
- Two tangent galvanometers A and B have coils of radii 8 cm and 16 cm respectively
- A solid sphere of mass M, radius R and having moment of inertia about an axis passing
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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