| ⇦ | 
| ⇨ |
The string of a pendulum is horizontal.The mass of bob attached to it is m.Now, the string is released.The tension in the string in the lowest position is
Options
(a) mg
(b) 2 mg
(c) 3 mg
(d) 4 mg
Correct Answer:
3 mg
Explanation:
When string is released, then according to conservation of energy,
(1/2) mv² = mgh
v² = 2gh = 2gR
Now, when it is at the bottom,
T – mg cos 0² = mv²/R
or T – mg = (m/R)(2gR)
T = mg + 2mg = 3mg.
Related Questions: - One coolie takes 1 minute to raise a suitcase through a height of 2 m
- An a.c. supply gives 30 volt r.m.s which passes through a 10Ω resistance.
- In a photoelectric effect experiment, the slope of the graph between the stopping
- A radiation of energy ‘E’ falls normally on a perfectly reflecting surface
- After 300 days, the activity of a radioactive sample is 5000 dps
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- One coolie takes 1 minute to raise a suitcase through a height of 2 m
- An a.c. supply gives 30 volt r.m.s which passes through a 10Ω resistance.
- In a photoelectric effect experiment, the slope of the graph between the stopping
- A radiation of energy ‘E’ falls normally on a perfectly reflecting surface
- After 300 days, the activity of a radioactive sample is 5000 dps
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply