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The string of a pendulum is horizontal.The mass of bob attached to it is m.Now, the string is released.The tension in the string in the lowest position is
Options
(a) mg
(b) 2 mg
(c) 3 mg
(d) 4 mg
Correct Answer:
3 mg
Explanation:
When string is released, then according to conservation of energy,
(1/2) mv² = mgh
v² = 2gh = 2gR
Now, when it is at the bottom,
T – mg cos 0² = mv²/R
or T – mg = (m/R)(2gR)
T = mg + 2mg = 3mg.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Carbon,silicon and germanium have four valence electrons each. At room temperature
- A particle moves in xy plane according to the equation x = 4t² + 5t + 16 and y = 5t
- The escape velocity of a body from earth’s surface is Ve. The escape velocity
- If temperature of gas increases from 27°C to 927°C, the kinetic energy will be
- An inclined plane of length 5.60m making an angle of 45⁰ with the horizontal is placed
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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