The second overtone of an open pipe is in resonance with the first overtone

⇦

⇨

The second overtone of an open pipe is in resonance with the first overtone of a closed pipe of length 2 m. Length of the open pipe is

Options

(a) 4 m
(b) 2 m
(c) 8 m
(d) 1 m

Correct Answer:

4 m

Explanation:

Frequency of second overtone of an open is ʋ = 3v / 2l₀ Frequency of first overtone of a closed pipe is ʋ’ = 3v / 4lc Given : ʋ = ʋ’ ⇒ 3v / 2l₀ = 3v / 4lc l₀ / lc = 2 ⇒ l₀ = 2lc = 2 × 2 = 4 m.

Related Questions:

1. A ball is thrown vertically downwards from a height of 20 m with an initially
2. A photosensitive metallic surface has work function, hν₀. If photons of energy
3. A ship A is moving westwards with a speed of 10 km/h .The time after
4. A battery charges a parallel plate capacitor seperated by distance(d) so that the energy
5. A tuning fork of frequency 512 Hz makes 4 beats per second with the vibrating string

Topics: Waves (80)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends