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If the density of earth is doubled keeping its radius constant then acceleration due to gravity will be (g=9.8 m/s²)
Options
(a) 19.6 m/s²
(b) 9.8 m/s²
(c) 4.9 m/s²
(d) 2.45 m/s²
Correct Answer:
19.6 m/s²
Explanation:
Acceleration due to gravity g=GM/R² ——-(1)
The radius is constant, volume also constant.
If volume is constant, density is proportional to mass.(v=m/ρ)
The density is doubled, the mass is also doubled. (M’=2M)
The new acceleration due to gravity g’=GM’/R’²
Put the value M’=2M and R’=R
g’=G(2M)/R²
g’=2GM/R² ——–(2)
Substituting equations (1) and (2), we get
g’=2g
g=9.8 m/s²
g’=2×9.8=19.6 m/s²
Related Questions: - The energy of a hydrogen atom in the ground state is – 13.6 eV. The energy of a He⁺ ion
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The energy of a hydrogen atom in the ground state is – 13.6 eV. The energy of a He⁺ ion
- A particle is under two mutually perpendicular simple harmonic motions
- Two liquid drops having diameters of 1 cm and 1.5 cm. The ratio of excess
- If the lattice parameter for a crystalline structure is 3.6 Å, then the atomic radius
- When the rate of flow of charge through a metallic conductor
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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